Optimal. Leaf size=291 \[ \frac{\left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right ) \left (a+b x^n\right )^{3/2} \sqrt{c+d x^n}}{96 b^2 d^3 n}-\frac{(b c-a d) \left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right ) \sqrt{a+b x^n} \sqrt{c+d x^n}}{64 b^2 d^4 n}+\frac{(b c-a d)^2 \left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x^n}}{\sqrt{b} \sqrt{c+d x^n}}\right )}{64 b^{5/2} d^{9/2} n}-\frac{(3 a d+7 b c) \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{24 b^2 d^2 n}+\frac{x^n \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{4 b d n} \]
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Rubi [A] time = 0.315857, antiderivative size = 291, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 30, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.233, Rules used = {446, 90, 80, 50, 63, 217, 206} \[ \frac{\left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right ) \left (a+b x^n\right )^{3/2} \sqrt{c+d x^n}}{96 b^2 d^3 n}-\frac{(b c-a d) \left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right ) \sqrt{a+b x^n} \sqrt{c+d x^n}}{64 b^2 d^4 n}+\frac{(b c-a d)^2 \left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x^n}}{\sqrt{b} \sqrt{c+d x^n}}\right )}{64 b^{5/2} d^{9/2} n}-\frac{(3 a d+7 b c) \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{24 b^2 d^2 n}+\frac{x^n \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{4 b d n} \]
Antiderivative was successfully verified.
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Rule 446
Rule 90
Rule 80
Rule 50
Rule 63
Rule 217
Rule 206
Rubi steps
\begin{align*} \int \frac{x^{-1+3 n} \left (a+b x^n\right )^{3/2}}{\sqrt{c+d x^n}} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{x^2 (a+b x)^{3/2}}{\sqrt{c+d x}} \, dx,x,x^n\right )}{n}\\ &=\frac{x^n \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{4 b d n}+\frac{\operatorname{Subst}\left (\int \frac{(a+b x)^{3/2} \left (-a c-\frac{1}{2} (7 b c+3 a d) x\right )}{\sqrt{c+d x}} \, dx,x,x^n\right )}{4 b d n}\\ &=-\frac{(7 b c+3 a d) \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{24 b^2 d^2 n}+\frac{x^n \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{4 b d n}+\frac{\left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \operatorname{Subst}\left (\int \frac{(a+b x)^{3/2}}{\sqrt{c+d x}} \, dx,x,x^n\right )}{48 b^2 d^2 n}\\ &=\frac{\left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \left (a+b x^n\right )^{3/2} \sqrt{c+d x^n}}{96 b^2 d^3 n}-\frac{(7 b c+3 a d) \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{24 b^2 d^2 n}+\frac{x^n \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{4 b d n}-\frac{\left ((b c-a d) \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{\sqrt{a+b x}}{\sqrt{c+d x}} \, dx,x,x^n\right )}{64 b^2 d^3 n}\\ &=-\frac{(b c-a d) \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \sqrt{a+b x^n} \sqrt{c+d x^n}}{64 b^2 d^4 n}+\frac{\left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \left (a+b x^n\right )^{3/2} \sqrt{c+d x^n}}{96 b^2 d^3 n}-\frac{(7 b c+3 a d) \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{24 b^2 d^2 n}+\frac{x^n \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{4 b d n}+\frac{\left ((b c-a d)^2 \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b x} \sqrt{c+d x}} \, dx,x,x^n\right )}{128 b^2 d^4 n}\\ &=-\frac{(b c-a d) \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \sqrt{a+b x^n} \sqrt{c+d x^n}}{64 b^2 d^4 n}+\frac{\left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \left (a+b x^n\right )^{3/2} \sqrt{c+d x^n}}{96 b^2 d^3 n}-\frac{(7 b c+3 a d) \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{24 b^2 d^2 n}+\frac{x^n \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{4 b d n}+\frac{\left ((b c-a d)^2 \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c-\frac{a d}{b}+\frac{d x^2}{b}}} \, dx,x,\sqrt{a+b x^n}\right )}{64 b^3 d^4 n}\\ &=-\frac{(b c-a d) \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \sqrt{a+b x^n} \sqrt{c+d x^n}}{64 b^2 d^4 n}+\frac{\left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \left (a+b x^n\right )^{3/2} \sqrt{c+d x^n}}{96 b^2 d^3 n}-\frac{(7 b c+3 a d) \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{24 b^2 d^2 n}+\frac{x^n \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{4 b d n}+\frac{\left ((b c-a d)^2 \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{1-\frac{d x^2}{b}} \, dx,x,\frac{\sqrt{a+b x^n}}{\sqrt{c+d x^n}}\right )}{64 b^3 d^4 n}\\ &=-\frac{(b c-a d) \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \sqrt{a+b x^n} \sqrt{c+d x^n}}{64 b^2 d^4 n}+\frac{\left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \left (a+b x^n\right )^{3/2} \sqrt{c+d x^n}}{96 b^2 d^3 n}-\frac{(7 b c+3 a d) \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{24 b^2 d^2 n}+\frac{x^n \left (a+b x^n\right )^{5/2} \sqrt{c+d x^n}}{4 b d n}+\frac{(b c-a d)^2 \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x^n}}{\sqrt{b} \sqrt{c+d x^n}}\right )}{64 b^{5/2} d^{9/2} n}\\ \end{align*}
Mathematica [A] time = 0.740804, size = 241, normalized size = 0.83 \[ \frac{3 (b c-a d)^{5/2} \left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right ) \sqrt{\frac{b \left (c+d x^n\right )}{b c-a d}} \sinh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x^n}}{\sqrt{b c-a d}}\right )-b \sqrt{d} \sqrt{a+b x^n} \left (c+d x^n\right ) \left (3 a^2 b d^2 \left (5 c-2 d x^n\right )+9 a^3 d^3-a b^2 d \left (145 c^2-92 c d x^n+72 d^2 x^{2 n}\right )+b^3 \left (-70 c^2 d x^n+105 c^3+56 c d^2 x^{2 n}-48 d^3 x^{3 n}\right )\right )}{192 b^3 d^{9/2} n \sqrt{c+d x^n}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.068, size = 0, normalized size = 0. \begin{align*} \int{{x}^{-1+3\,n} \left ( a+b{x}^{n} \right ) ^{{\frac{3}{2}}}{\frac{1}{\sqrt{c+d{x}^{n}}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x^{n} + a\right )}^{\frac{3}{2}} x^{3 \, n - 1}}{\sqrt{d x^{n} + c}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.38324, size = 1335, normalized size = 4.59 \begin{align*} \left [\frac{3 \,{\left (35 \, b^{4} c^{4} - 60 \, a b^{3} c^{3} d + 18 \, a^{2} b^{2} c^{2} d^{2} + 4 \, a^{3} b c d^{3} + 3 \, a^{4} d^{4}\right )} \sqrt{b d} \log \left (8 \, b^{2} d^{2} x^{2 \, n} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} + 4 \,{\left (2 \, \sqrt{b d} b d x^{n} +{\left (b c + a d\right )} \sqrt{b d}\right )} \sqrt{b x^{n} + a} \sqrt{d x^{n} + c} + 8 \,{\left (b^{2} c d + a b d^{2}\right )} x^{n}\right ) + 4 \,{\left (48 \, b^{4} d^{4} x^{3 \, n} - 105 \, b^{4} c^{3} d + 145 \, a b^{3} c^{2} d^{2} - 15 \, a^{2} b^{2} c d^{3} - 9 \, a^{3} b d^{4} - 8 \,{\left (7 \, b^{4} c d^{3} - 9 \, a b^{3} d^{4}\right )} x^{2 \, n} + 2 \,{\left (35 \, b^{4} c^{2} d^{2} - 46 \, a b^{3} c d^{3} + 3 \, a^{2} b^{2} d^{4}\right )} x^{n}\right )} \sqrt{b x^{n} + a} \sqrt{d x^{n} + c}}{768 \, b^{3} d^{5} n}, -\frac{3 \,{\left (35 \, b^{4} c^{4} - 60 \, a b^{3} c^{3} d + 18 \, a^{2} b^{2} c^{2} d^{2} + 4 \, a^{3} b c d^{3} + 3 \, a^{4} d^{4}\right )} \sqrt{-b d} \arctan \left (\frac{{\left (2 \, \sqrt{-b d} b d x^{n} +{\left (b c + a d\right )} \sqrt{-b d}\right )} \sqrt{b x^{n} + a} \sqrt{d x^{n} + c}}{2 \,{\left (b^{2} d^{2} x^{2 \, n} + a b c d +{\left (b^{2} c d + a b d^{2}\right )} x^{n}\right )}}\right ) - 2 \,{\left (48 \, b^{4} d^{4} x^{3 \, n} - 105 \, b^{4} c^{3} d + 145 \, a b^{3} c^{2} d^{2} - 15 \, a^{2} b^{2} c d^{3} - 9 \, a^{3} b d^{4} - 8 \,{\left (7 \, b^{4} c d^{3} - 9 \, a b^{3} d^{4}\right )} x^{2 \, n} + 2 \,{\left (35 \, b^{4} c^{2} d^{2} - 46 \, a b^{3} c d^{3} + 3 \, a^{2} b^{2} d^{4}\right )} x^{n}\right )} \sqrt{b x^{n} + a} \sqrt{d x^{n} + c}}{384 \, b^{3} d^{5} n}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x^{n} + a\right )}^{\frac{3}{2}} x^{3 \, n - 1}}{\sqrt{d x^{n} + c}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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